$\frac{x}{x-4}\le\frac{x-4}{x}$
$r^2-9$
$8y^2x^3\cdot6x^2$
$\frac{d^2}{dx^2}\left(9x^2+y^2=9\right)$
$\int_{-\infty}^1\frac{3x^3+5x}{x^2+1}dx$
$2\left(x+1\right)-3x\ge-5$
$\lim_{x\to\infty}\left(\frac{12x^4-3x+6}{5x^5+4x^4}\right)$
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