$4+13+33$
$\left(2x-4\right)\left(3x-6\right)$
$\frac{1}{sinx}+\frac{1}{cosx}=\frac{\left(sinx+cosx\right)\left(tan^2x+1\right)}{tanx}$
$sin\:4x=-\frac{2\sqrt{3}}{3}$
$\int cos\left(13-6x\right)dx$
$\lim_{x\to1}\left(\frac{4x^2-4}{x-1}\right)$
$4=3-\cos\left(x+\frac{\pi}{4}\right)$
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