$\arccoth\left(\sqrt{4}\right)$

$\left(2h^2\cdot3h^3\right)^2$

$\lim_{x\to\frac{5\pi}{4}}\left(\frac{\left(1-2csc2x\right)}{2x}\right)$

$\left(x^2y+y\right)\frac{dy}{dx}-x$

$tan^2x+4\sqrt{3}=7$

$\tan\left(x\right)\left(\frac{5}{12}\right)$

$\int\frac{x^2-6}{\left(x+2\right)\left(2x-1\right)}dx$