$\int\tan\left(x\right)^4\sec\left(x\right)dx$
$a+b=4$
$\frac{dy}{dx}\sqrt{x}-\sqrt{y}=8$
$-9,1q+6,2q+3,2q$
$\frac{1}{x}=\frac{3}{3x-1}$
$\frac{16-9x^6}{4-3x^3}$
$\frac{-9x^2+x^4+x-3}{x+3}$
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