$x+\:\frac{4}{x}=-2$
$x^4-4\cdot x^3\cdot x^2-12x$
$49x^2-y^6t^4$
$2\left|\left(x+1\right)\left(x+2\right)\right|$
$e^{-y}dx+e^{-x}\left(e^{-y}+1\right)dy=0$
$\frac{d}{dx}y=\frac{6}{y^3}-2x$
$1-6x-9x^2$
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