$\int\sin\pi dx$
$3\left(2x+1\right)>1\left(2x-2\right)$
$\left(t+4\right)^2$
$\frac{\left(2x\right)}{\left(x+1\right)}+\frac{x+6}{\left(x+1\right)^2}$
$8+\left\{-5-\left\{2+9\right\}\right\}-4+7$
$-845+350-1235$
$82-45$
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