$4.-1$
$\left(x^2-2x\right)\left(3x^2+4x-7\right)$
$\frac{sin\:-\:sin^3}{cos^2}=\:\frac{1}{csc}$
$13\:-\:\left(-4\right)\:$
$\lim\:_{x\to\:\infty}\left(-15x^2+10x^3\right)$
$\left(-7x-7\right)-\left(2x+3\right)$
$\frac{3x^3-5x^2+17x-18}{x-2}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!