$a^2+3a-40$
$\lim_{x\to1}\left(\frac{7^x\:-6^x-1}{x^2-1}\right)$
$\lim_{x\to\infty}\left(\frac{e\left(x^5\right)}{4-x^6}\right)$
$m^2+m^2$
$14x^2\:-\:\frac{2}{3}x$
$x^3\cdot y^{-5}$
$\left(b+9\right)\cdot\left(b-8\right)$
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