$\left|-6\right|-\left|3\right|$
$\left(\frac{2x^3}{3}\right)^3$
$\frac{x}{2}-7=9$
$2x^2-4x+3$
$-19\cdot37$
$4y-4y+1$
$( n ^ { 2 } - 1 ) ( n ^ { 2 } + 7 ) ( n ^ { 4 } - 6 n ^ { 2 } - 7 )$
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