$\frac{dy}{dx}=3x^2\sin\left(3x^3\right)$
$3ln\left(x^{\frac{2}{5}}\right)+ln\left(2x\right)$
$\left(x^3\cdot\:\:y^4-8\right)^2$
$5-4x<-11$
$\frac{3}{2}x^3:3x^2$
$\frac{\left(4h^5\right)^2}{20h^8}$
$\frac{-112}{16}$
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