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Exercise

cot⁡(−5x33−2)\cot\left(\sqrt[3]{-5x^3}-2\right)

Step-by-step Solution

1

Applying the trigonometric identity: cot⁡(θ)=cos⁡(θ)sin⁡(θ)\cot\left(\theta \right) = \frac{\cos\left(\theta \right)}{\sin\left(\theta \right)}

cos⁡(−5x33−2)sin⁡(−5x33−2)\frac{\cos\left(\sqrt[3]{-5x^3}-2\right)}{\sin\left(\sqrt[3]{-5x^3}-2\right)}
Why does cot(x) = cos(x)/sin(x) ?

Final answer to the exercise

cos⁡(−5x33−2)sin⁡(−5x33−2)\frac{\cos\left(\sqrt[3]{-5x^3}-2\right)}{\sin\left(\sqrt[3]{-5x^3}-2\right)}

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cot(3√−5x3−2)
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