$\left(\frac{1}{6\:}a^2-\frac{3}{2}a\right)$
$\frac{2x^2}{\left(x+1\right)\left(x+2\right)}$
$\left(4ab^2\right)\left(x+3\right)$
$y=\ln\left(-x^2+6x\right)$
$2x^{-2}-7x^{-1}-15=0$
$-3n>4n-7$
$2a-5a^2$
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