$x^2-17x+60=0$
$\left(5x^3+3y\right)^2$
$-5q-2+2q-8$
$\frac{\left(7x-8\right)}{5x+3}=x$
$3-\left(-4\right)+5-\left|2-\left(4-\left(-7\right)+10\right)\right|$
$\lim_{x\to0}\left(\frac{y^2}{1-3\cos\left(y\right)}\right)$
$8z^3-64w^3$
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