$\int_{-\infty}^{05}22xe^{-2x^2}dx$
$\left(-m^2a^2\right)^6$
$\int\left(x^2+1\right)y^{-x}dx$
$-11-\left(-12\right)$
$x^2+72x+x$
$2x+3x-5x+10x$
$sin\left(10x\right)cos\left(6x\right)=\frac{\left(cos\left(16x\right)-cos\left(-4x\right)\right)}{2}$
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