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Solving: (sin⁡(35)−sin⁡(23))cos⁡()\left(\sin\left(\frac{3}{5}\right)-\sin\left(\frac{2}{3}\right)\right)\cos\left(\right)
Solve instead: cos⁡(sin⁡(35)−sin⁡(23))\cos\left(\sin\left(\frac{3}{5}\right)-\sin\left(\frac{2}{3}\right)\right)

Exercise

cos⁡(sin⁡(35)−sin⁡(23))\cos\left(\sin\left(\frac{3}{5}\right)-\sin\left(\frac{2}{3}\right)\right)

Step-by-step Solution

1

Multiply the single term cos⁡()\cos\left(\right) by each term of the polynomial (sin⁡(35)−sin⁡(23))\left(\sin\left(\frac{3}{5}\right)-\sin\left(\frac{2}{3}\right)\right)

sin⁡(35)cos⁡()−sin⁡(23)cos⁡()\sin\left(\frac{3}{5}\right)\cos\left(\right)-\sin\left(\frac{2}{3}\right)\cos\left(\right)

Final answer to the exercise

sin⁡(35)cos⁡()−sin⁡(23)cos⁡()\sin\left(\frac{3}{5}\right)\cos\left(\right)-\sin\left(\frac{2}{3}\right)\cos\left(\right)

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cos(sin(35 )−sin(23 ))
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