$3x^3+9x^2+9x+3$
$1+2-3+4-5-6$
$\sqrt{\frac{\left(-8\right)^3}{\left(-2\right)^5}}$
$\frac{1}{3}\cos^2x=\frac{1}{2}\left(1-\sin\left(x\right)\right)$
$x^4+5x^3$
$4\left(9\right)^2+3\left(9\right)-3$
$2\left(3x-5\right)^2+1$
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