$\frac{\left(1-2x\right)^5}{3+4x}$

$-2x\left(e^y\right)y'=2\left(\left(e^y\right)+\left(\left(x^3\right)\left(e^{\left(2x\right)}\right)\right)\right)$

$\frac{dy}{dx}=\frac{-.7}{cos\left(y\right)}$

$-3w^2-3v-7w+4v+7w^2$

$\left(6x\:+\:5\right)^2$

$15x-10=80$

$8b\:-\:5\:-\:3b$