$x'=x^3$
$\frac{8}{x}<4$
$-4-12-\left[\left(-13-20+8\right)-4\right]$
$c^2+11c+24$
$\left(5\right)\left(mx+7m\right)$
$4x=2y$
$\int sec\left(24x\right)tan\left(24x\right)dx$
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