$\frac{3x+9x^2}{3x}$
$\frac{-6x-5}{3}<\frac{4x-4}{2}$
$x^2+13x+0$
$\frac{d}{dx}\left(\frac{e^{x^2}}{\sqrt{8-x^5}}\right)$
$4x-8=7x-2$
$160+0.15x=292$
$1x^4-8x+16$
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