$5x^2+y^2=0$
$\int ya^ydx$
$x^3-3x^2+x+1$
$\int_{-\infty\:}^0\:xe^{4x^2-1}dx$
$\left(\frac{3}{4}+\frac{1}{2}\left(\frac{1}{2}\right)\right)$
$10^16$
$5x\cdot\left(-3y\right)$
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