$\left(4x^3-4y^3\right)^2$
$\left(\frac{24x+7}{6}\right)^2$
$\left(x\right)\frac{dy}{dx}=\left(1-4x^2\right)\tan\left(y\right)$
$\lim_{x\to\infty}\left(\frac{x+2e^{2x}}{3x^2+e^{2x}}\right)$
$b^2-12+36$
$\left(-19\right)\cdot\left(-146820\right)$
$m^6-n^6$
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