$400m^{10}+40m^5+1$
$4x-5y+6x-2$
$\frac{2y^3}{3y}$
$\left(a^4+3ab^2\right)\left(a^4+5b^2c\right)$
$-15.42\ge-17.42-g$
$\frac{5}{2}a^5\:.\:\frac{5}{3}a^5$
$5\cdot\sin\left(x\right)\cdot\tan\left(x\right)-\sin\left(x\right)-5\cdot\tan\left(x\right)+1=0$
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