$16+6\left(3x\right)-\left(3x\right)^2$
$9\:+\:4b\:=\:17$
$\int\frac{10}{\left(x-3\right)\left(x^2+9\right)}dx$
$\left(2x^3-6y^4\right)^2$
$\frac{dy}{dx}=x+u+ux$
$7x^8\cdot6x^3$
$\left(2s-2\right)\left(2s+2\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!