16x2+12x=016x^2+12x=016x2+12x=0
limx→∞(1−22x−1)3x−1\lim_{x\to\infty}\left(1-\frac{2}{2x-1}\right)^{3x-1}x→∞lim(1−2x−12)3x−1
∫1b(1x2x2−1)dx\int_1^b\left(\frac{1}{x\sqrt{2x^2-1}}\right)dx∫1b(x2x2−11)dx
20.69\sqrt[0.69]{2}0.692
9p − 5q + 2p9p\:-\:5q\:+\:2p9p−5q+2p
2y.2y.2y.2y2y.2y.2y.2y2y.2y.2y.2y
4x≥204x\ge204x≥20
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