$\frac{3}{5}+\frac{1}{2}x\ge\frac{3}{4}x+9$
$2ab-4a$
$\sin\left(60^{\circ}\right)=\frac{12}{x}$
$\left(-13m^2n^4\right)\left(2m^3n^2\right)$
$y = 3 x ^ { 3 } + \frac { 6 } { x ^ { 2 } }$
$100a^4b^6-400a^2b^4$
$\arcsin\left(1.6\right)$
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