−15⋅24-15\cdot24−15⋅24
1(2+5x)3\frac{1}{\left(2+5x\right)^3}(2+5x)31
3a2−a−103a^2-a-103a2−a−10
−x+1>2x+4-x+1>2x+4−x+1>2x+4
(5m2+1)3\left(5m^2+1\right)^3(5m2+1)3
3 a2 b3− 40 d; a=2 ;b=3; d=123\:a^2\:b^3-\:40\:d;\:a=2\:;b=3;\:d=\frac{1}{2}3a2b3−40d;a=2;b=3;d=21
42a43x3y\frac{42a^4}{3x^3y}3x3y42a4
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