$sen^2\left(0\right)$
$\frac{9a^2b^4}{3b}$
$\left(\frac{4}{7}x-\frac{5}{3}\right)^2$
$\lim_{x\to\infty}e^{-2x}$
$\frac{5.2}{0.078}=\frac{x}{3.6}$
$\frac{12x^5y^{-2}z^{2q}}{7x^{p+4}y^{-5}z^{3q-5}}$
$7\left(-5\right)-3\left(-8\right)$
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