x+8>−9x+8>-9x+8>−9
t−1t+1t-\frac{1}{t+1}t−t+11
f(x)=(3x3−4x)xf\left(x\right)=\frac{\left(3x^3-4x\right)}{x}f(x)=x(3x3−4x)
(3x2−3y3)(5x2+3y3)\left(3x^2-3y^3\right)\left(5x^2+3y^3\right)(3x2−3y3)(5x2+3y3)
52−20s+1005^2-20s+10052−20s+100
(−57)−(−35)\left(-57\right)-\left(-35\right)(−57)−(−35)
4xx−1+2≥0\frac{4x}{x-1}+2\ge0x−14x+2≥0
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