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Solve the rational equation $y=\frac{x^3-6x^2-8x}{\left(x^3-6x^2-8x\right)^2-1}$

Step-by-step Solution

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Solution

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Final answer to the problem

$y=\frac{x^3-6x^2-8x}{x^2\left(x^2-6x-8\right)^2-1}$
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Step-by-step Solution

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Learn how to solve rational equations problems step by step online. Solve the rational equation y=(x^3-6x^2-8x)/((x^3-6x^2-8x)^2-1). Factor the polynomial \left(x^3-6x^2-8x\right) by it's greatest common factor (GCF): x. The power of a product is equal to the product of it's factors raised to the same power.

Final answer to the problem

$y=\frac{x^3-6x^2-8x}{x^2\left(x^2-6x-8\right)^2-1}$

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Function Plot

Plotting: $y+\frac{-x^3+6x^2+8x}{\left(x^3-6x^2-8x\right)^2-1}$

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a
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d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{4}{x+2}=\frac{6}{x-2}$

$\frac{3}{x+1}-\frac{1}{2}=\frac{1}{3x+3}$

$\frac{2x+4}{5x}=\frac{2}{x}$

$\frac{5}{x-7}=\frac{2}{x-2}$

$\frac{2x+3}{3x}=\frac{x}{2x-3}$

$\frac{x+1}{x-2}=\frac{x-3}{x}$

$\frac{x}{2}=\frac{8}{x}$

Main Topic: Rational Equations

Rational or fractional equations are those equations that contain algebraic fractions, and where the variable or unknown appears in the denominator of at least one of those fractions.

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