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Solve the equation with radicals $y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{\left(x^2+4x\right)^{7}}$

Step-by-step Solution

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Solution

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Final answer to the problem

$y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{x^2+4x+4-4^{7}}$
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Step-by-step Solution

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Learn how to solve equations with cubic roots problems step by step online. Solve the equation with radicals y=(2x+3)^5(x-1)^(1/3)(x^2+4x)^(7/2). Factor the polynomial x^2+4x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 4. Divide 4 by 2. Divide 4 by 2. Calculate the power 2^2.

Final answer to the problem

$y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{x^2+4x+4-4^{7}}$

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Function Plot

Plotting: $y-\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{\left(x^2+4x\right)^{7}}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\sqrt[3]{5x+4}=4$

$\sqrt[3]{1-5x}=-4$

$\sqrt[3]{x-3}=2$

$2\left(7b-1\right)^{\frac{1}{3}}-4=0$

$2\left(7b-1\right)^{\frac{1}{3}}=-4$

$\sqrt[3]{x=6}$

$30x^{\frac{1}{3}}y^{\frac{2}{3}}=384000$

Main Topic: Equations with Cubic Roots

Those equations that they degree (greatest exponent) equals 3.

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