$2x-4x-16$
$8x+15+6a+6\:$
$x^2-13x+40=0$
$\left(4z+2w\right)^3$
$\frac{1}{-3x}\left(6-2y\right)$
$\left(3x^2\:-\:2x\:+\:7\right)\:\left(x\:-\:9\right)$
$2\:-\:\left[16\:-\:\left(4\:+3\right)\right]$
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