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Solve the differential equation $x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0$

Step-by-step Solution

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Solution

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Final answer to the problem

$y=\sqrt{-x^2+C_1},\:y=-\sqrt{-x^2+C_1}$
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Step-by-step Solution

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Learn how to solve integrals of polynomial functions problems step by step online. Solve the differential equation x^(-2)y^(-5)dx+x^(-3)y^(-4)dy=0. Grouping the terms of the differential equation. Grouping the terms of the differential equation. Simplify the fraction \frac{-x^{-2}y^{-5}}{x^{-3}} by x. Subtract the values 3 and -2.

Final answer to the problem

$y=\sqrt{-x^2+C_1},\:y=-\sqrt{-x^2+C_1}$

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Function Plot

Plotting: $x^{-2}y^{-5}dx+x^{-3}y^{-4}dy$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{dy}{dx}=e^{x-y}+e^x+e^{-y}+1$

$\frac{dy}{dx}=\left(x-y+5\right)^2$

$x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0$

$\frac{dy}{dx}=\left(x+y\right)^2$

$\frac{dy}{dx}=ay$

$x\frac{dy}{dx}-y=2x^2y$

$\frac{dy}{dx}=2\left(1+x\right)\left(1+y^2\right)$

Main Topic: Integrals of Polynomial Functions

Integrals of polynomial functions.

Used Formulas

See formulas (2)

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