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Simplify $\sin\left(x^3\ln\left(y^2\right)\right)+\sqrt[3]{y^2-2y+1=e^{\left(\left(x^2-1\right)^4\right)}}$ applying logarithm properties

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Solution

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Final answer to the problem

$\sin\left(x^3\ln\left(y^2\right)\right)+\sqrt[3]{\left(y-1\right)^{2}=e^{\left(\left(x^2-1\right)^4\right)}}$
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Step-by-step Solution

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Learn how to solve perfect square trinomial problems step by step online. Simplify sin(x^3ln(y^2))+(y^2-2y+1=e^(x^2-1)^4)^(1/3) applying logarithm properties. The trinomial y^2-2y+1 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial.

Final answer to the problem

$\sin\left(x^3\ln\left(y^2\right)\right)+\sqrt[3]{\left(y-1\right)^{2}=e^{\left(\left(x^2-1\right)^4\right)}}$

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Function Plot

Plotting: $\sin\left(x^3\ln\left(y^2\right)\right)+\sqrt[3]{\left(y-1\right)^{2}=e^{\left(\left(x^2-1\right)^4\right)}}$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

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$factor\left(x^3-7x+6\right)$

$factor\left(x^3+2x^2-x-2\right)$

$factor\left(x^3-4x^2+x+6\right)$

Main Topic: Perfect Square Trinomial

Perfect Square Trinomials have first and last terms that are positive perfect squares. And the middle term is twice the product of the square roots of the first and third terms. The sign of the middle term will tell us whether the factorization will involve a binomial that is either a sum or a difference (signs need to match)

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