$\sqrt{4.18}$
$\log\left(x+3\right)+\log\left(x-5\right)=\log\left(x-6\right)$
$\lim_{x\to\infty}\left(\frac{x^2-1}{\:1-e^x}\right)$
$\frac{d^2}{dydx}=x\sec\left(y\right)$
$2x^3-5x^2+6x-72$
$\left(2b+3c\right)^2$
$-6\left(10x-10\right)-5$
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