$5\left(-5+2a\right)$
$\frac{\left(\left(2y^3\right)^3\right)}{\left(\left(3y^6\right)^2\right)}$
$\lim_{h\to2}\:8-4h$
$-3x=15$
$u^2+u-6=0$
$-2x\:-\:\left(3x\:+\:2x\:-\:x\right)\:+\:8x$
$3x^2=-6x$
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