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Solve the inequality $\left(x-4\right)^2+y\leq -12+\left(x-2\right)^2$

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Solution

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Final answer to the problem

$x\leq 6$
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Step-by-step Solution

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Learn how to solve inequalities problems step by step online. Solve the inequality (x-4)^2+y<=-12+(x-2)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Moving the term 16 to the other side of the inequation with opposite sign. Subtract the values -12 and -16. Expand \left(x-2\right)^2.

Final answer to the problem

$x\leq 6$

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Plotting: $x\leq 6$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Inequalities

In mathematics, an inequation is a statement that an inequality holds between two values. It is usually written in the form of a pair of expressions denoting the values in question, with a relational sign between them indicating the specific inequality relation.

Used Formulas

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