$\:-2.\:\left(-1+9\right)\:-\:\left(-6\:-\:15:\:3\right)$
$\frac{tanx}{\sqrt{tan^2x+1}}=sinx$
$\int-\tan\left(\frac{y}{2}\right)dy$
$-3a^xm+9y^3-2a^xm-8y^3$
$5m^2\left(4m-3\right)$
$3.77\cdot1.875$
$\frac{1}{\:5}\sqrt{5}x\:\frac{1}{2}\sqrt[3]{2}x\sqrt[6]{80}x\sqrt[3]{5}$
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