Final answer to the problem
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
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Step-by-step Solution
1
The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
Final answer to the problem
$\frac{dy}{dz}y^{zy}+\ln\left(y\right)-\ln\left(xz\right)=\sqrt{3^{xy}+y}+y^x$
