$\sqrt[3]{3^4.x^3}.\sqrt[3]{3^2.x^4}$
$\frac{1}{3}x\left(x-27\right)$
$\left(3j-7k\right)\cdot\left(2k+3\right)$
$\left(4x+3y+2z\right)^2$
$5x+6=10+12y$
$\frac{dy}{dx}=-\frac{1}{50}\left(y-25\right)$
$\left(t+4\right)\left(t+4\right)$
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