$\frac{1}{x-1}<\frac{1}{x+1}$
$\frac{\left(33\right)}{3}$
$\frac{1}{4}-\frac{x^2}{9}$
$\sqrt{\left(1-\sin^2\left(b\right)\right)}\tan\left(b\right)=\sin\left(b\right)$
$\frac{x^3-4x^2-3x+2}{x-2}$
$y=7x^{-x}$
$-\frac{4-x}{2}\le\frac{3}{4}x+\frac{1}{2}$
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