$\frac{1+\sin x}{\cos^2\left(x\right)}=\tan^2x+1+\tan x\sec x$
$\left(2c+5\right)\left(2c+6\right)$
$\sqrt{\left(13\:+\:11^2\right)\:+\:\left(4\:+\:14^2\right)}$
$\cos x\left(1-\cos2x\right)$
$\lim_{x\to2}\left(5x^2-3x+2\right)$
$5\left(x-3\right)=2\left(-x+7\right)-1$
$\sec^2x\cot^2x\:=\:\csc^2x$
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