$\frac{4x-2+3x+3}{6}$
$x^2\ge x+1$
$\frac{d}{dx}\left(arctan\left(-5x\right)\right)$
$\int\left(2x-3\right)^3\cdot e^{9x}dx$
$-10\:\:4\:+\:8\:-\:\left[-2\:+\:5\:-\:\left(3\:+\:1\right)\right]\:-\:8$
$\left(-6xy^5\right)^3$
$\int\frac{x}{25+4x^2}dx$
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