$11x\ge\:27$
$4x+12y-2=0$
$\frac{dy}{dx}=x+6$
$\frac{d}{dx}y=2\cot8x^4$
$x^2\:+\:4y^2=4$
$x^6-x^3+\frac{2}{4}$
$\left(1+x\right)\tan\left(y\right)\frac{dy}{dx}=x$
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