$\left(\:-\:4\right)\left(\:+3\right)\left(+5\right)\left(-2\right)\left(-3\right)\left(-6\right)\left(+8\right)$
$\sqrt[3]{2.52}$
$2x^2+2y$
$x^2-2x<8$
$\frac{x^{-1}}{x^2}$
$6\left(x\:-\:1\right)\:=\:42$
$\lim_{x\to1}\left(\frac{9^x-8^x-1}{x^2-1}\right)$
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