$x^2+1\cdot2x-3$
$\left(1+2x+3x^2\right)\left(4-5x\right)^3$
$\left(6a-4b+24\right)^2$
$\lim_{x\to0}\left(\frac{x^2}{ln\left(1+3x\right)}\right)$
$\frac{x^2}{4}+4y^2$
$\int\frac{x^2-2x-1}{x^2+1}dx$
$6.14-27$
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