$\frac{dy}{dx}=\left(3-x\right)\left(2+y\right)$
$a^2+b^2=100$
$3x-8\le\frac{7}{3}x-5$
$7y\cdot y'=x,7y=9$
$\left(3a+4g\right)^2$
$\left(3x^2\:-\:2y^3\right)\:^4$
$\left(x+1\right)\left(x-1\right)+\left(3+x\left(3-x\right)\right)$
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