$\frac{x\:3\:-4\:x\:2\:-7\:x+2\:6}{x-4}$
$\lim_{x\to0}\left(\frac{tan^2\left(4x\right)}{sin^2\left(3x\right)cos^2\left(2x\right)}\right)$
$\int\left(16x^2\right)dx$
$\left(-22\right)\:-\:\left(-23\right)\:+\:\left(+15\right)\:+\:\left(-13\right)\:+\:\left(-17\right)$
$\frac{\left(4a\right)^2}{4a^9}$
$\int\frac{1}{u^2+4}du$
$\frac{cot^2x+8cotx+16}{cosx\:cotx+4cosx}$
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