$\left(4-2y+y^2\right)\left(16+2y^3-y^4-8y\right)-y^6-60$
$5^3\cdot25$
$\int\:\left(4t^2+\frac{t}{6}\right)dx$
$3142\cdot3-57\cdot4^2+12$
$\int x\cdot\cos\left(x^2\right)$
$\frac{3x^5}{6x^{-2}}$
$\int\ln\left(8r+6\right)dr$
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