$\sqrt{4+6\cdot10+3\left(5^2-2\right)}$
$\int w^2\sec^2w^3dw$
$3x-4\cdot\:5x+4$
$\frac{d}{dx}y\sqrt{x+4}=xy+8$
$\frac{8m^9n^6-4}{2m^3n^2-2}$
$y'+3y=x+e^{\left(-2x\right)}$
$\sqrt{a}-\frac{1}{2}\sqrt{a}+3\sqrt{a}$
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