$2a^2+a=1$
$\left(4x^3+\:2x\right)^3$
$\frac{\sin\left(b\right)}{1+\sec\left(b\right)}=\frac{\sin\left(b\right)}{1-\sec\left(b\right)}-2\cot\left(b\right)$
$x\:+-10=-15$
$x\:\:por\:\:x+3\:$
$-8x^2.5x^4$
$\left(x+2\right)\left(-2x+3y\right)$
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